A 10 g block placed on a rough horizontal floor is being pulled by a constant force 50 N. Coefficient of kinetic friction between the block and the floor is 0.4. Find work done by each individual force acting on the block over displacement of 5 m.

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Given, mass m=10 g
Constant force F=50 N
Coefficient of kinetic friction, μ=0.4
Displacement, s = 5m ,
Forces acting on the block are its weight (mg = 100).
Normal reaction (N=100 N) from the ground, force due to kinetic friction
F= μmg = 40N and the applied force (F= 
50 N) which are shown in the given figure.

Work done W , by the gravity, i.e., 
weight of the block Wgravity = 0 J : (mgs)
Work done by the normal reaction Wnormal = 0J (Ns)
Work done by the applied force Wext = 500x5 = 250J
Work done by the force of kinetic friction Wfriction = 40x5
Wfriction = - 200J (Fand s are antiparallel)